10x^2-20x+68=0

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Solution for 10x^2-20x+68=0 equation: 



10x^2-20x+68=0

a = 10; b = -20; c = +68;
Δ = b2-4ac
Δ = -202-4·10·68
Δ = -2320
Delta is less than zero, so there is no solution for the equation

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